If (10) 9 + 2(11) 1 (10) 8 + 3(11) 2 (10) 7 + . . . . . . . . + 10 (11) 9 = k(10) 9 , then k is equal to
Text Solution
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Let s = (10) 9 + 2(11) 1 (10) 8 + 3 (11) 2 (10) 7 +......................+10(11) 9
∴ s
= (11) 1 (10) 8 + 2(11) 2 (10) 7 + .................+9(11) 9 + (11) 10
substract
s = (10) 9 + (11) 1 (10) 8 + (11) 2 (10) 7 + ................+(11) 9 – (11) 10
⇒ –
s =
– (11) 10 –
s =10 9
–(11) 10
⇒ –
s = –10 10 + 11 10 – 11 10 ∴ s = 10 11
∴ given 10 11 = k(10) 9 ∴ k = 100
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